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Scan and read Data Matrix barcodes from image files is one of the barcode decoding functions in . NET Barcode Reader component. To help . net developers ... Note that the result for the variance in Equation 539 requires the random variables to be independent. To see why the independence is important, consider the following simple examX1. Clearly, X1 and X2 are not indeple. Let X1 denote any random variable and de ne X2 pendent. In fact, XY 1. Now, Y X1 X2 is 0 with probability 1. Therefore, V(Y) 0, regardless of the variances of X1 and X2. EXAMPLE 535 In 3, we found that if Y is a negative binomial random variable with parameters p and r, Y X1 X2 p Xr, where each Xi is a geometric random variable with parameter p and they are independent. Therefore, E1Xi 2 1 p and E1Xi 2 11 p2 p2 . From Equation 2 537, E1Y 2 r p and from Equation 539, V 1Y 2 r11 p2 p . An approach similar to the one applied in the above example can be used to verify the formulas for the mean and variance of an Erlang random variable in 4. EXAMPLE 536 Suppose the random variables X1 and X2 denote the length and width, respectively, of a manufactured part. Assume E(X1) 2 centimeters with standard deviation 0.1 centimeter and E(X2) 5 centimeters with standard deviation 0.2 centimeter. Also, assume that the covariance between X1 and X2 is 0.005. Then, Y 2X1 2X2 is a random variable that represents the perimeter of the part. From Equation 536, E1Y 2 and from Equation 538 V1Y2 22 10.12 2 22 10.22 2 0.04 0.16 0.04 2 2 21 0.0052 0.16 centimeters squared 0.4 centimeters. 2122 2152 14 centimeters .net code 39 reader: Barcode Reader App for . NET  Code 39 C# & VB. NET Recognition ... .net data matrix reader Barcode Reader for . NET  How to Scan Data Matrix Using C# & VB ...
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Read Code39, Code128, PDF417, DataMatrix , QR, and other barcodes from TIF, PDF and other image documents. Notice that in order for this scheme to make any sense, multiplication must be noncommutative8 ; otherwise, squaring (e.7), we would find k 2 = 1 instead of (C.8). At this point, the reader might be wondering whether we will find out next that in order to have a consistent scheme, we require yet another fifth, sixth, seventh dimension, and so on, never stopping. Well, part of the beauty of this is that four dimensions is just enough to make the entire scheme selfconsistent, as we will show now. Multiplying (e.7) by k from the left and using (e.8), we find that kj = i. (C.9) The particular linear combination that represents the average of p random variables, with identical means and variances, is used quite often in the subsequent chapters. We highlight the results for this special case. .net data matrix reader Best 20 NuGet datamatrix Packages  NuGet Must Haves Package
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